A bacterial cell undergoes binary fission eve | vedclass

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(C) The total time given is $3$ hours,which is equal to $3 	imes 60 = 180$ minutes.The number of generations $(n)$ is calculated by dividing the tota

Vedclass · Accepted Answer

$512$

Vedclass · Answer

(C) The total time given is $3$ hours,which is equal to $3 	imes 60 = 180$ minutes.The number of generations $(n)$ is calculated by dividing the total time by the time taken for one division: $n = 180 / 20 = 9$ generations.The number of bacteria produced after $n$ generations is given by the formula $2^n$.Therefore,the number of bacteria = $2^9 = 512$.

$A$ bacterial cell undergoes binary fission every $20$ minutes. Starting with a single bacterium,how many bacteria will be produced at the end of $3$ hours?

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